Solve [2-3+x-2)-3

$$[ 2 - 3 + x - 2 ) - 3$$

Evaluate

$$x-6$$

Solution Steps

Subtract 3 from 2 to get -1.

$$-1+x-2-3$$

Subtract 2 from -1 to get -3.

$$-3+x-3$$

Subtract 3 from -3 to get -6.

$$-6+x$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Subtract 3 from 2 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-1+x-2-3)$$

Subtract 2 from -1 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3+x-3)$$

Subtract 3 from -3 to get -6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-6+x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$