Solve [2-(-1/2)]*(-1/2+3)=

$$[ 2 - ( - \frac { 1 } { 2 } ) ] \cdot ( - \frac { 1 } { 2 } + 3 ) =$$

Evaluate

$$\frac{25}{4}=6.25$$

Solution Steps

The opposite of -\frac{1}{2} is \frac{1}{2}.

$$\left(2+\frac{1}{2}\right)\left(-\frac{1}{2}+3\right)$$

Convert 2 to fraction \frac{4}{2}.

$$\left(\frac{4}{2}+\frac{1}{2}\right)\left(-\frac{1}{2}+3\right)$$

Since \frac{4}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{4+1}{2}\left(-\frac{1}{2}+3\right)$$

Add 4 and 1 to get 5.

$$\frac{5}{2}\left(-\frac{1}{2}+3\right)$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{5}{2}\left(-\frac{1}{2}+\frac{6}{2}\right)$$

Since -\frac{1}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$\frac{5}{2}\times \frac{-1+6}{2}$$

Add -1 and 6 to get 5.

$$\frac{5}{2}\times \frac{5}{2}$$

Multiply \frac{5}{2} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 5}{2\times 2}$$

Do the multiplications in the fraction \frac{5\times 5}{2\times 2}.

$$\frac{25}{4}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {2}} = 6\frac{1}{4} = 6.25$$