Solve [2^{-1}+3^0+5^1+7^2+9^3]

$$[ 2 ^ { - 1 } + 3 ^ { 0 } + 5 ^ { 1 } + 7 ^ { 2 } + 9 ^ { 3 } ]$$

Evaluate

$$\frac{1569}{2}=784.5$$

Solution Steps

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$\frac{1}{2}+3^{0}+5^{1}+7^{2}+9^{3}$$

Calculate 3 to the power of 0 and get 1.

$$\frac{1}{2}+1+5^{1}+7^{2}+9^{3}$$

Add \frac{1}{2} and 1 to get \frac{3}{2}.

$$\frac{3}{2}+5^{1}+7^{2}+9^{3}$$

Calculate 5 to the power of 1 and get 5.

$$\frac{3}{2}+5+7^{2}+9^{3}$$

Add \frac{3}{2} and 5 to get \frac{13}{2}.

$$\frac{13}{2}+7^{2}+9^{3}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{13}{2}+49+9^{3}$$

Add \frac{13}{2} and 49 to get \frac{111}{2}.

$$\frac{111}{2}+9^{3}$$

Calculate 9 to the power of 3 and get 729.

$$\frac{111}{2}+729$$

Add \frac{111}{2} and 729 to get \frac{1569}{2}.

$$\frac{1569}{2}$$

Factor

$$\frac{3 \cdot 523}{2} = 784\frac{1}{2} = 784.5$$