Solve [-2+3-(2-5)+3]-[(3-5+2)-2+(3-4)]

$$[ - 2 + 3 - ( 2 - 5 ) + 3 ] - [ ( 3 - 5 + 2 ) - 2 + ( 3 - 4 ) ]$$

Evaluate

$$10$$

Solution Steps

Add -2 and 3 to get 1.

$$1-\left(2-5\right)+3-\left(3-5+2-2+3-4\right)$$

Subtract 5 from 2 to get -3.

$$1-\left(-3\right)+3-\left(3-5+2-2+3-4\right)$$

The opposite of -3 is 3.

$$1+3+3-\left(3-5+2-2+3-4\right)$$

Add 1 and 3 to get 4.

$$4+3-\left(3-5+2-2+3-4\right)$$

Add 4 and 3 to get 7.

$$7-\left(3-5+2-2+3-4\right)$$

Subtract 5 from 3 to get -2.

$$7-\left(-2+2-2+3-4\right)$$

Add -2 and 2 to get 0.

$$7-\left(-2+3-4\right)$$

Add -2 and 3 to get 1.

$$7-\left(1-4\right)$$

Subtract 4 from 1 to get -3.

$$7-\left(-3\right)$$

The opposite of -3 is 3.

$$7+3$$

Add 7 and 3 to get 10.

$$10$$

Factor

$$2\times 5$$