Solve [(8,2*10^4+4,8*10^2):10^-6]*10^-5

$$[ ( 8,2 \cdot 10 ^ { 4 } + 4,8 \cdot 10 ^ { 2 } ) : 10 ^ { - 6 } ] \cdot 10 ^ { - 5 }$$

Evaluate

$$824800$$

Solution Steps

Calculate 10 to the power of 4 and get 10000.

$$\frac{8,2\times 10000+4,8\times 10^{2}}{10^{-6}}\times 10^{-5}$$

Multiply 8,2 and 10000 to get 82000.

$$\frac{82000+4,8\times 10^{2}}{10^{-6}}\times 10^{-5}$$

Calculate 10 to the power of 2 and get 100.

$$\frac{82000+4,8\times 100}{10^{-6}}\times 10^{-5}$$

Multiply 4,8 and 100 to get 480.

$$\frac{82000+480}{10^{-6}}\times 10^{-5}$$

Add 82000 and 480 to get 82480.

$$\frac{82480}{10^{-6}}\times 10^{-5}$$

Calculate 10 to the power of -6 and get \frac{1}{1000000}.

$$\frac{82480}{\frac{1}{1000000}}\times 10^{-5}$$

Divide 82480 by \frac{1}{1000000} by multiplying 82480 by the reciprocal of \frac{1}{1000000}.

$$82480\times 1000000\times 10^{-5}$$

Multiply 82480 and 1000000 to get 82480000000.

$$82480000000\times 10^{-5}$$

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$82480000000\times \frac{1}{100000}$$

Multiply 82480000000 and \frac{1}{100000} to get 824800.

$$824800$$

Factor

$$1031\times 2^{5}\times 5^{2}$$