Solve [(6+7+8+8+8+9+9)-(6+9)]*3*6div10

$$[ ( 6 + 7 + 8 + 8 + 8 + 9 + 9 ) - ( 6 + 9 ) ] \cdot 3 \cdot 6 \div 10$$

Evaluate

$$72$$

Solution Steps

Add 6 and 7 to get 13.

$$\frac{\left(13+8+8+8+9+9-\left(6+9\right)\right)\times 3\times 6}{10}$$

Add 13 and 8 to get 21.

$$\frac{\left(21+8+8+9+9-\left(6+9\right)\right)\times 3\times 6}{10}$$

Add 21 and 8 to get 29.

$$\frac{\left(29+8+9+9-\left(6+9\right)\right)\times 3\times 6}{10}$$

Add 29 and 8 to get 37.

$$\frac{\left(37+9+9-\left(6+9\right)\right)\times 3\times 6}{10}$$

Add 37 and 9 to get 46.

$$\frac{\left(46+9-\left(6+9\right)\right)\times 3\times 6}{10}$$

Add 46 and 9 to get 55.

$$\frac{\left(55-\left(6+9\right)\right)\times 3\times 6}{10}$$

Add 6 and 9 to get 15.

$$\frac{\left(55-15\right)\times 3\times 6}{10}$$

Subtract 15 from 55 to get 40.

$$\frac{40\times 3\times 6}{10}$$

Multiply 40 and 3 to get 120.

$$\frac{120\times 6}{10}$$

Multiply 120 and 6 to get 720.

$$\frac{720}{10}$$

Divide 720 by 10 to get 72.

$$72$$

Factor

$$2^{3}\times 3^{2}$$