Solve [(-a)^3]^2+a^4*a^2=

$$[ ( - a ) ^ { 3 } ] ^ { 2 } + a ^ { 4 } \cdot a ^ { 2 } =$$

Evaluate

$$2a^{6}$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$\left(-a\right)^{6}+a^{4}a^{2}$$

To multiply powers of the same base, add their exponents. Add 4 and 2 to get 6.

$$\left(-a\right)^{6}+a^{6}$$

Expand \left(-a\right)^{6}.

$$\left(-1\right)^{6}a^{6}+a^{6}$$

Calculate -1 to the power of 6 and get 1.

$$1a^{6}+a^{6}$$

Combine 1a^{6} and a^{6} to get 2a^{6}.

$$2a^{6}$$

Expand

$$2a^{6}$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$\left(-a\right)^{6}+a^{4}a^{2}$$

To multiply powers of the same base, add their exponents. Add 4 and 2 to get 6.

$$\left(-a\right)^{6}+a^{6}$$

Expand \left(-a\right)^{6}.

$$\left(-1\right)^{6}a^{6}+a^{6}$$

Calculate -1 to the power of 6 and get 1.

$$1a^{6}+a^{6}$$

Combine 1a^{6} and a^{6} to get 2a^{6}.

$$2a^{6}$$