Solve [(-3)^{2}]^{6}*(0^1*0^2-0^3)^2=

$$[ ( - 3 ) ^ { 2 } ] ^ { 6 } \cdot ( 0 ^ { 1 } \cdot 0 ^ { 2 } - 0 ^ { 3 } ) ^ { 2 } =$$

Evaluate

$$0$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 6 to get 12.

$$\left(-3\right)^{12}\left(0^{1}\times 0^{2}-0^{3}\right)^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\left(-3\right)^{12}\left(0^{3}-0^{3}\right)^{2}$$

Calculate -3 to the power of 12 and get 531441.

$$531441\left(0^{3}-0^{3}\right)^{2}$$

Calculate 0 to the power of 3 and get 0.

$$531441\left(0-0^{3}\right)^{2}$$

Calculate 0 to the power of 3 and get 0.

$$531441\left(0-0\right)^{2}$$

Subtracting 0 from itself leaves 0.

$$531441\times 0^{2}$$

Calculate 0 to the power of 2 and get 0.

$$531441\times 0$$

Multiply 531441 and 0 to get 0.

$$0$$

Factor

$$0$$