Solve [(-2+3)+8-(3-2)]:(-2)^3-2^7:(-2)^6+(-3)

$$[ ( - 2 + 3 ) + 8 - ( 3 - 2 ) ] : ( - 2 ) ^ { 3 } - 2 ^ { 7 } : ( - 2 ) ^ { 6 } + ( - 3 )$$

Evaluate

$$-6$$

Solution Steps

Add -2 and 3 to get 1.

$$\frac{1+8-\left(3-2\right)}{\left(-2\right)^{3}}-\frac{2^{7}}{\left(-2\right)^{6}}-3$$

Add 1 and 8 to get 9.

$$\frac{9-\left(3-2\right)}{\left(-2\right)^{3}}-\frac{2^{7}}{\left(-2\right)^{6}}-3$$

Subtract 2 from 3 to get 1.

$$\frac{9-1}{\left(-2\right)^{3}}-\frac{2^{7}}{\left(-2\right)^{6}}-3$$

Subtract 1 from 9 to get 8.

$$\frac{8}{\left(-2\right)^{3}}-\frac{2^{7}}{\left(-2\right)^{6}}-3$$

Calculate -2 to the power of 3 and get -8.

$$\frac{8}{-8}-\frac{2^{7}}{\left(-2\right)^{6}}-3$$

Divide 8 by -8 to get -1.

$$-1-\frac{2^{7}}{\left(-2\right)^{6}}-3$$

Calculate 2 to the power of 7 and get 128.

$$-1-\frac{128}{\left(-2\right)^{6}}-3$$

Calculate -2 to the power of 6 and get 64.

$$-1-\frac{128}{64}-3$$

Divide 128 by 64 to get 2.

$$-1-2-3$$

Subtract 2 from -1 to get -3.

$$-3-3$$

Subtract 3 from -3 to get -6.

$$-6$$

Factor

$$-6$$