Solve [1/5*(-3/12)]^2+[7/5*5/12]

$$[ \frac { 1 } { 5 } \times ( \frac { - 3 } { 12 } ) ] ^ { 2 } + [ \frac { 7 } { 5 } \times \frac { 5 } { 12 } ]$$

Evaluate

$$\frac{703}{1200}\approx 0.585833333$$

Solution Steps

Reduce the fraction \frac{-3}{12} to lowest terms by extracting and canceling out 3.

$$\left(\frac{1}{5}\left(-\frac{1}{4}\right)\right)^{2}+\frac{7}{5}\times \frac{5}{12}$$

Multiply \frac{1}{5} and -\frac{1}{4} to get -\frac{1}{20}.

$$\left(-\frac{1}{20}\right)^{2}+\frac{7}{5}\times \frac{5}{12}$$

Calculate -\frac{1}{20} to the power of 2 and get \frac{1}{400}.

$$\frac{1}{400}+\frac{7}{5}\times \frac{5}{12}$$

Multiply \frac{7}{5} and \frac{5}{12} to get \frac{7}{12}.

$$\frac{1}{400}+\frac{7}{12}$$

Add \frac{1}{400} and \frac{7}{12} to get \frac{703}{1200}.

$$\frac{703}{1200}$$

Factor

$$\frac{19 \cdot 37}{2 ^ {4} \cdot 3 \cdot 5 ^ {2}} = 0.5858333333333333$$