Solve =y^2=8

$$= y ^ { 2 } = 8$$

Solve for y

$$y=2\sqrt{2}\approx 2.828427125$$

$$y=-2\sqrt{2}\approx -2.828427125$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$y=2\sqrt{2} y=-2\sqrt{2}$$

Steps Using the Quadratic Formula

Subtract 8 from both sides.

$$y^{2}-8=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-8\right)}}{2}$$

Square 0.

$$y=\frac{0±\sqrt{-4\left(-8\right)}}{2}$$

Multiply -4 times -8.

$$y=\frac{0±\sqrt{32}}{2}$$

Take the square root of 32.

$$y=\frac{0±4\sqrt{2}}{2}$$

Now solve the equation y=\frac{0±4\sqrt{2}}{2} when ± is plus.

$$y=2\sqrt{2}$$

Now solve the equation y=\frac{0±4\sqrt{2}}{2} when ± is minus.

$$y=-2\sqrt{2}$$

The equation is now solved.

$$y=2\sqrt{2} y=-2\sqrt{2}$$