Solve =x^2+3x+1/x^2

$$= x ^ { 2 } + 3 x + \frac { 1 } { x ^ { 2 } }$$

Evaluate

$$x^{2}+3x+\frac{1}{x^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{2}+3x times \frac{x^{2}}{x^{2}}.

$$\frac{\left(x^{2}+3x\right)x^{2}}{x^{2}}+\frac{1}{x^{2}}$$

Since \frac{\left(x^{2}+3x\right)x^{2}}{x^{2}} and \frac{1}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\left(x^{2}+3x\right)x^{2}+1}{x^{2}}$$

Do the multiplications in \left(x^{2}+3x\right)x^{2}+1.

$$\frac{x^{4}+3x^{3}+1}{x^{2}}$$

Factor

$$\frac{x^{4}+3x^{3}+1}{x^{2}}$$