Solve =t^2-3t-3/t+1*t

$$= t ^ { 2 } - 3 t - \frac { 3 } { t } + 1 \cdot t$$

Evaluate

$$t^{2}-2t-\frac{3}{t}$$

Short Solution Steps

Combine -3t and 1t to get -2t.

$$t^{2}-2t-\frac{3}{t}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply t^{2}-2t times \frac{t}{t}.

$$\frac{\left(t^{2}-2t\right)t}{t}-\frac{3}{t}$$

Since \frac{\left(t^{2}-2t\right)t}{t} and \frac{3}{t} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(t^{2}-2t\right)t-3}{t}$$

Do the multiplications in \left(t^{2}-2t\right)t-3.

$$\frac{t^{3}-2t^{2}-3}{t}$$

Factor

$$\frac{t^{3}-2t^{2}-3}{t}$$