Solve for f
f=2x-5+\frac{7}{x}
x\neq 0
Solve for x (complex solution)
x=\frac{-\sqrt{f^{2}+10f-31}+f+5}{4}
x=\frac{\sqrt{f^{2}+10f-31}+f+5}{4}
Solve for x
x=\frac{-\sqrt{f^{2}+10f-31}+f+5}{4}
x=\frac{\sqrt{f^{2}+10f-31}+f+5}{4}\text{, }f\geq 2\sqrt{14}-5\text{ or }f\leq -2\sqrt{14}-5
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fx=2x^{2}-5x+7
Combine 5x^{2} and -3x^{2} to get 2x^{2}.
xf=2x^{2}-5x+7
The equation is in standard form.
\frac{xf}{x}=\frac{2x^{2}-5x+7}{x}
Divide both sides by x.
f=\frac{2x^{2}-5x+7}{x}
Dividing by x undoes the multiplication by x.
f=2x-5+\frac{7}{x}
Divide 2x^{2}-5x+7 by x.
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