Solve =41*4+(4-10*1/4)

$$= 41 \times 4 + ( 4 - 10 \times \frac { 1 } { 4 } )$$

Evaluate

$$\frac{331}{2}=165.5$$

Solution Steps

Multiply 41 and 4 to get 164.

$$164+4-10\times \frac{1}{4}$$

Multiply 10 and \frac{1}{4} to get \frac{10}{4}.

$$164+4-\frac{10}{4}$$

Reduce the fraction \frac{10}{4} to lowest terms by extracting and canceling out 2.

$$164+4-\frac{5}{2}$$

Convert 4 to fraction \frac{8}{2}.

$$164+\frac{8}{2}-\frac{5}{2}$$

Since \frac{8}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$164+\frac{8-5}{2}$$

Subtract 5 from 8 to get 3.

$$164+\frac{3}{2}$$

Convert 164 to fraction \frac{328}{2}.

$$\frac{328}{2}+\frac{3}{2}$$

Since \frac{328}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$\frac{328+3}{2}$$

Add 328 and 3 to get 331.

$$\frac{331}{2}$$

Factor

$$\frac{331}{2} = 165\frac{1}{2} = 165.5$$