Solve =240*295

$$= 240 \times 295$$

Evaluate

$$70800$$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}240\\\underline{\times\phantom{99}295}\\\end{array}$$

Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 240 with 5. Write the result 1200 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}240\\\underline{\times\phantom{99}295}\\\phantom{\times9}1200\\\end{array}$$

Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 240 with 9. Write the result 2160 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}240\\\underline{\times\phantom{99}295}\\\phantom{\times9}1200\\\phantom{\times}2160\phantom{9}\\\end{array}$$

Now multiply the first number with the 3^{rd} digit in 2^{nd} number to get intermediate results. That is Multiply 240 with 2. Write the result 480 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}240\\\underline{\times\phantom{99}295}\\\phantom{\times9}1200\\\phantom{\times}2160\phantom{9}\\\underline{\phantom{\times}480\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}240\\\underline{\times\phantom{99}295}\\\phantom{\times9}1200\\\phantom{\times}2160\phantom{9}\\\underline{\phantom{\times}480\phantom{99}}\\\phantom{\times}70800\end{array}$$

Factor

$$2^{4}\times 3\times 5^{2}\times 59$$