Solve =2x-4quady=-1/2x+1

$$= 2 x - 4 \quad y = - \frac { 1 } { 2 } x + 1$$

Solve for x

$$x=\frac{8y+2}{5}$$

Steps for Solving Linear Equation

Add \frac{1}{2}x to both sides.

$$2x-4y+\frac{1}{2}x=1$$

Combine 2x and \frac{1}{2}x to get \frac{5}{2}x.

$$\frac{5}{2}x-4y=1$$

Add 4y to both sides.

$$\frac{5}{2}x=1+4y$$

The equation is in standard form.

$$\frac{5}{2}x=4y+1$$

Divide both sides of the equation by \frac{5}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{2}x}{\frac{5}{2}}=\frac{4y+1}{\frac{5}{2}}$$

Dividing by \frac{5}{2} undoes the multiplication by \frac{5}{2}.

$$x=\frac{4y+1}{\frac{5}{2}}$$

Divide 1+4y by \frac{5}{2} by multiplying 1+4y by the reciprocal of \frac{5}{2}.

$$x=\frac{8y+2}{5}$$

Solve for y

$$y=\frac{5x}{8}-\frac{1}{4}$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$-4y=-\frac{1}{2}x+1-2x$$

Combine -\frac{1}{2}x and -2x to get -\frac{5}{2}x.

$$-4y=-\frac{5}{2}x+1$$

The equation is in standard form.

$$-4y=-\frac{5x}{2}+1$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{-\frac{5x}{2}+1}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{-\frac{5x}{2}+1}{-4}$$

Divide -\frac{5x}{2}+1 by -4.

$$y=\frac{5x}{8}-\frac{1}{4}$$