Solve =2-3*(-5)-[-(-4)+(-3)-2-3]+(-3-2)*(+3)

$$= 2 - 3 \times ( - 5 ) - [ - ( - 4 ) + ( - 3 ) - 2 - 3 ] + ( - 3 - 2 ) \times ( + 3 )$$

Evaluate

$$6$$

Solution Steps

Multiply 3 and -5 to get -15.

$$2-\left(-15\right)-\left(-\left(-4\right)-3-2-3\right)+\left(-3-2\right)\times 3$$

The opposite of -15 is 15.

$$2+15-\left(-\left(-4\right)-3-2-3\right)+\left(-3-2\right)\times 3$$

Add 2 and 15 to get 17.

$$17-\left(-\left(-4\right)-3-2-3\right)+\left(-3-2\right)\times 3$$

The opposite of -4 is 4.

$$17-\left(4-3-2-3\right)+\left(-3-2\right)\times 3$$

Subtract 3 from 4 to get 1.

$$17-\left(1-2-3\right)+\left(-3-2\right)\times 3$$

Subtract 2 from 1 to get -1.

$$17-\left(-1-3\right)+\left(-3-2\right)\times 3$$

Subtract 3 from -1 to get -4.

$$17-\left(-4\right)+\left(-3-2\right)\times 3$$

The opposite of -4 is 4.

$$17+4+\left(-3-2\right)\times 3$$

Add 17 and 4 to get 21.

$$21+\left(-3-2\right)\times 3$$

Subtract 2 from -3 to get -5.

$$21-5\times 3$$

Multiply -5 and 3 to get -15.

$$21-15$$

Subtract 15 from 21 to get 6.

$$6$$

Factor

$$2\times 3$$