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2\times 3\sqrt{10}-5\sqrt{40}
Factor 90=3^{2}\times 10. Rewrite the square root of the product \sqrt{3^{2}\times 10} as the product of square roots \sqrt{3^{2}}\sqrt{10}. Take the square root of 3^{2}.
6\sqrt{10}-5\sqrt{40}
Multiply 2 and 3 to get 6.
6\sqrt{10}-5\times 2\sqrt{10}
Factor 40=2^{2}\times 10. Rewrite the square root of the product \sqrt{2^{2}\times 10} as the product of square roots \sqrt{2^{2}}\sqrt{10}. Take the square root of 2^{2}.
6\sqrt{10}-10\sqrt{10}
Multiply -5 and 2 to get -10.
-4\sqrt{10}
Combine 6\sqrt{10} and -10\sqrt{10} to get -4\sqrt{10}.