Solve =144.5+[40/2-(3+5+9)/12]

$$= 144.5 + [ \frac { \frac { 40 } { 2 } - ( 3 + 5 + 9 ) } { 12 } ]$$

Evaluate

$$144.75$$

Solution Steps

Divide 40 by 2 to get 20.

$$144.5+\frac{20-\left(3+5+9\right)}{12}$$

Add 3 and 5 to get 8.

$$144.5+\frac{20-\left(8+9\right)}{12}$$

Add 8 and 9 to get 17.

$$144.5+\frac{20-17}{12}$$

Subtract 17 from 20 to get 3.

$$144.5+\frac{3}{12}$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$144.5+\frac{1}{4}$$

Convert decimal number 144.5 to fraction \frac{1445}{10}. Reduce the fraction \frac{1445}{10} to lowest terms by extracting and canceling out 5.

$$\frac{289}{2}+\frac{1}{4}$$

Least common multiple of 2 and 4 is 4. Convert \frac{289}{2} and \frac{1}{4} to fractions with denominator 4.

$$\frac{578}{4}+\frac{1}{4}$$

Since \frac{578}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{578+1}{4}$$

Add 578 and 1 to get 579.

$$\frac{579}{4}$$

Factor

$$\frac{3 \cdot 193}{2 ^ {2}} = 144\frac{3}{4} = 144.75$$