Solve =1+4+4/24u-2

$$= 1 + 4 + \frac { 4 } { 24 u } - 2$$

Evaluate

$$3+\frac{1}{6u}$$

Short Solution Steps

Add 1 and 4 to get 5.

$$5+\frac{4}{24u}-2$$

Subtract 2 from 5 to get 3.

$$3+\frac{4}{24u}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{24u}{24u}.

$$\frac{3\times 24u}{24u}+\frac{4}{24u}$$

Since \frac{3\times 24u}{24u} and \frac{4}{24u} have the same denominator, add them by adding their numerators.

$$\frac{3\times 24u+4}{24u}$$

Do the multiplications in 3\times 24u+4.

$$\frac{72u+4}{24u}$$

Factor the expressions that are not already factored in \frac{72u+4}{24u}.

$$\frac{4\left(18u+1\right)}{24u}$$

Cancel out 4 in both numerator and denominator.

$$\frac{18u+1}{6u}$$

Factor

$$\frac{18u+1}{6u}$$