Solve =(3)-40-(+28)-(-19)+(-24)-(-32)(4)-2/3+(-1/6)-

$$= ( 3 ) - 40 - ( + 28 ) - ( - 19 ) + ( - 24 ) - ( - 32 ) ( 4 ) - \frac { 2 } { 3 } + ( - \frac { 1 } { 6 } ) -$$

Evaluate

$$\frac{343}{6}\approx 57.166666667$$

Solution Steps

Subtract 40 from 3 to get -37.

$$-37-28-\left(-19\right)-24-\left(-32\times 4\right)-\frac{2}{3}-\frac{1}{6}$$

Subtract 28 from -37 to get -65.

$$-65-\left(-19\right)-24-\left(-32\times 4\right)-\frac{2}{3}-\frac{1}{6}$$

The opposite of -19 is 19.

$$-65+19-24-\left(-32\times 4\right)-\frac{2}{3}-\frac{1}{6}$$

Add -65 and 19 to get -46.

$$-46-24-\left(-32\times 4\right)-\frac{2}{3}-\frac{1}{6}$$

Subtract 24 from -46 to get -70.

$$-70-\left(-32\times 4\right)-\frac{2}{3}-\frac{1}{6}$$

Multiply -32 and 4 to get -128.

$$-70-\left(-128\right)-\frac{2}{3}-\frac{1}{6}$$

The opposite of -128 is 128.

$$-70+128-\frac{2}{3}-\frac{1}{6}$$

Add -70 and 128 to get 58.

$$58-\frac{2}{3}-\frac{1}{6}$$

Convert 58 to fraction \frac{174}{3}.

$$\frac{174}{3}-\frac{2}{3}-\frac{1}{6}$$

Since \frac{174}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{174-2}{3}-\frac{1}{6}$$

Subtract 2 from 174 to get 172.

$$\frac{172}{3}-\frac{1}{6}$$

Least common multiple of 3 and 6 is 6. Convert \frac{172}{3} and \frac{1}{6} to fractions with denominator 6.

$$\frac{344}{6}-\frac{1}{6}$$

Since \frac{344}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{344-1}{6}$$

Subtract 1 from 344 to get 343.

$$\frac{343}{6}$$

Factor

$$\frac{7 ^ {3}}{2 \cdot 3} = 57\frac{1}{6} = 57.166666666666664$$