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676\left(\sqrt{3}\right)^{2}+1872\sqrt{3}+1296
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(-26\sqrt{3}-36\right)^{2}.
676\times 3+1872\sqrt{3}+1296
The square of \sqrt{3} is 3.
2028+1872\sqrt{3}+1296
Multiply 676 and 3 to get 2028.
3324+1872\sqrt{3}
Add 2028 and 1296 to get 3324.
676\left(\sqrt{3}\right)^{2}+1872\sqrt{3}+1296
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(-26\sqrt{3}-36\right)^{2}.
676\times 3+1872\sqrt{3}+1296
The square of \sqrt{3} is 3.
2028+1872\sqrt{3}+1296
Multiply 676 and 3 to get 2028.
3324+1872\sqrt{3}
Add 2028 and 1296 to get 3324.