Solve =(sqrt{2}+sqrt{3}-sqrt{6}+sqrt{2}-sqrt{3}+sqrt{6})x

$$= ( \sqrt { 2 } + \sqrt { 3 } - \sqrt { 6 } + \sqrt { 2 } - \sqrt { 3 } + \sqrt { 6 } ) x$$

Evaluate

$$2\sqrt{2}x$$

Solution Steps

Combine \sqrt{2} and \sqrt{2} to get 2\sqrt{2}.

$$\left(2\sqrt{2}+\sqrt{3}-\sqrt{6}-\sqrt{3}+\sqrt{6}\right)x$$

Combine \sqrt{3} and -\sqrt{3} to get 0.

$$\left(2\sqrt{2}-\sqrt{6}+\sqrt{6}\right)x$$

Combine -\sqrt{6} and \sqrt{6} to get 0.

$$2\sqrt{2}x$$

Differentiate w.r.t. x

$$2 \sqrt{2} = 2.828427125$$