Solve =(1.5/1.67-1)(1/20cm-1/-40cm)

$$= ( \frac { 1.5 } { 1.67 } - 1 ) ( \frac { 1 } { 20 cm } - \frac { 1 } { - 40 cm } )$$

Evaluate

$$-\frac{51}{6680cm}$$

Short Solution Steps

Expand \frac{1.5}{1.67} by multiplying both numerator and the denominator by 100.

$$\left(\frac{150}{167}-1\right)\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

Convert 1 to fraction \frac{167}{167}.

$$\left(\frac{150}{167}-\frac{167}{167}\right)\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

Since \frac{150}{167} and \frac{167}{167} have the same denominator, subtract them by subtracting their numerators.

$$\frac{150-167}{167}\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

Subtract 167 from 150 to get -17.

$$-\frac{17}{167}\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 20cm and -40cm is 40cm. Multiply \frac{1}{20cm} times \frac{2}{2}. Multiply \frac{1}{-40cm} times \frac{-1}{-1}.

$$-\frac{17}{167}\left(\frac{2}{40cm}-\frac{-1}{40cm}\right)$$

Since \frac{2}{40cm} and \frac{-1}{40cm} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{17}{167}\times \frac{2-\left(-1\right)}{40cm}$$

Do the multiplications in 2-\left(-1\right).

$$-\frac{17}{167}\times \frac{2+1}{40cm}$$

Do the calculations in 2+1.

$$-\frac{17}{167}\times \frac{3}{40cm}$$

Multiply -\frac{17}{167} times \frac{3}{40cm} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-17\times 3}{167\times 40cm}$$

Multiply -17 and 3 to get -51.

$$\frac{-51}{167\times 40cm}$$

Multiply 167 and 40 to get 6680.

$$\frac{-51}{6680cm}$$

Expand

$$-\frac{51}{6680cm}$$

Short Solution Steps

Expand \frac{1.5}{1.67} by multiplying both numerator and the denominator by 100.

$$\left(\frac{150}{167}-1\right)\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

Convert 1 to fraction \frac{167}{167}.

$$\left(\frac{150}{167}-\frac{167}{167}\right)\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

Since \frac{150}{167} and \frac{167}{167} have the same denominator, subtract them by subtracting their numerators.

$$\frac{150-167}{167}\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

Subtract 167 from 150 to get -17.

$$-\frac{17}{167}\left(\frac{1}{20cm}-\frac{1}{-40cm}\right)$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 20cm and -40cm is 40cm. Multiply \frac{1}{20cm} times \frac{2}{2}. Multiply \frac{1}{-40cm} times \frac{-1}{-1}.

$$-\frac{17}{167}\left(\frac{2}{40cm}-\frac{-1}{40cm}\right)$$

Since \frac{2}{40cm} and \frac{-1}{40cm} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{17}{167}\times \frac{2-\left(-1\right)}{40cm}$$

Do the multiplications in 2-\left(-1\right).

$$-\frac{17}{167}\times \frac{2+1}{40cm}$$

Do the calculations in 2+1.

$$-\frac{17}{167}\times \frac{3}{40cm}$$

Multiply -\frac{17}{167} times \frac{3}{40cm} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-17\times 3}{167\times 40cm}$$

Multiply -17 and 3 to get -51.

$$\frac{-51}{167\times 40cm}$$

Multiply 167 and 40 to get 6680.

$$\frac{-51}{6680cm}$$