Solve =sqrt{3}(x+1)=sqrt{6}

$$= \sqrt{ 3 } (x+1)= \sqrt{ 6 }$$

Solve for x

$$x=\sqrt{2}-1\approx 0.414213562$$

Steps for Solving Linear Equation

Use the distributive property to multiply \sqrt{3} by x+1.

$$\sqrt{3}x+\sqrt{3}=\sqrt{6}$$

Subtract \sqrt{3} from both sides.

$$\sqrt{3}x=\sqrt{6}-\sqrt{3}$$

Divide both sides by \sqrt{3}.

$$\frac{\sqrt{3}x}{\sqrt{3}}=\frac{\sqrt{6}-\sqrt{3}}{\sqrt{3}}$$

Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.

$$x=\frac{\sqrt{6}-\sqrt{3}}{\sqrt{3}}$$

Divide \sqrt{6}-\sqrt{3} by \sqrt{3}.

$$x=\sqrt{2}-1$$