Solve =60/360*22/7*(6)^2

$$= \frac { 60 } { 360 } \times \frac { 22 } { 7 } \times ( 6 ) ^ { 2 }$$

Evaluate

$$\frac{132}{7}\approx 18.857142857$$

Solution Steps

Reduce the fraction \frac{60}{360} to lowest terms by extracting and canceling out 60.

$$\frac{1}{6}\times \frac{22}{7}\times 6^{2}$$

Multiply \frac{1}{6} times \frac{22}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 22}{6\times 7}\times 6^{2}$$

Do the multiplications in the fraction \frac{1\times 22}{6\times 7}.

$$\frac{22}{42}\times 6^{2}$$

Reduce the fraction \frac{22}{42} to lowest terms by extracting and canceling out 2.

$$\frac{11}{21}\times 6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{11}{21}\times 36$$

Express \frac{11}{21}\times 36 as a single fraction.

$$\frac{11\times 36}{21}$$

Multiply 11 and 36 to get 396.

$$\frac{396}{21}$$

Reduce the fraction \frac{396}{21} to lowest terms by extracting and canceling out 3.

$$\frac{132}{7}$$

Factor

$$\frac{2 ^ {2} \cdot 3 \cdot 11}{7} = 18\frac{6}{7} \approx 18.857142857$$