Solve =1/49(4184-428^2/50)

$$= \frac { 1 } { 49 } ( 4184 - \frac { 428 ^ { 2 } } { 50 } )$$

Evaluate

$$\frac{13008}{1225}\approx 10.61877551$$

Solution Steps

Calculate 428 to the power of 2 and get 183184.

$$\frac{1}{49}\left(4184-\frac{183184}{50}\right)$$

Reduce the fraction \frac{183184}{50} to lowest terms by extracting and canceling out 2.

$$\frac{1}{49}\left(4184-\frac{91592}{25}\right)$$

Convert 4184 to fraction \frac{104600}{25}.

$$\frac{1}{49}\left(\frac{104600}{25}-\frac{91592}{25}\right)$$

Since \frac{104600}{25} and \frac{91592}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{49}\times \frac{104600-91592}{25}$$

Subtract 91592 from 104600 to get 13008.

$$\frac{1}{49}\times \frac{13008}{25}$$

Multiply \frac{1}{49} times \frac{13008}{25} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 13008}{49\times 25}$$

Do the multiplications in the fraction \frac{1\times 13008}{49\times 25}.

$$\frac{13008}{1225}$$

Factor

$$\frac{2 ^ {4} \cdot 3 \cdot 271}{5 ^ {2} \cdot 7 ^ {2}} = 10\frac{758}{1225} = 10.618775510204081$$