Solve =1/126+1/294+1/168quadC

$$= \frac { 1 } { 126 } + \frac { 1 } { 294 } + \frac { 1 } { 168 } \quad C$$

Evaluate

$$\frac{C}{168}+\frac{5}{441}$$

Solution Steps

Least common multiple of 126 and 294 is 882. Convert \frac{1}{126} and \frac{1}{294} to fractions with denominator 882.

$$\frac{7}{882}+\frac{3}{882}+\frac{1}{168}C$$

Since \frac{7}{882} and \frac{3}{882} have the same denominator, add them by adding their numerators.

$$\frac{7+3}{882}+\frac{1}{168}C$$

Add 7 and 3 to get 10.

$$\frac{10}{882}+\frac{1}{168}C$$

Reduce the fraction \frac{10}{882} to lowest terms by extracting and canceling out 2.

$$\frac{5}{441}+\frac{1}{168}C$$

Factor

$$\frac{21C+40}{3528}$$

Solution Steps

Factor out \frac{1}{3528}.

$$\frac{40+21C}{3528}$$

Consider 28+12+21C. Multiply and combine like terms.

$$21C+40$$

Rewrite the complete factored expression.

$$\frac{21C+40}{3528}$$