Solve =(2y^2-3-y)y/(y-4)(y+1)(2y-3)

$$= \frac { ( 2 y ^ { 2 } - 3 - y ) y } { ( y - 4 ) ( y + 1 ) ( 2 y - 3 ) }$$

Evaluate

$$\frac{y}{y-4}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{y\left(2y-3\right)\left(y+1\right)}{\left(y-4\right)\left(2y-3\right)\left(y+1\right)}$$

Cancel out \left(2y-3\right)\left(y+1\right) in both numerator and denominator.

$$\frac{y}{y-4}$$

Expand

$$\frac{y}{y-4}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{y\left(2y-3\right)\left(y+1\right)}{\left(y-4\right)\left(2y-3\right)\left(y+1\right)}$$

Cancel out \left(2y-3\right)\left(y+1\right) in both numerator and denominator.

$$\frac{y}{y-4}$$