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Solve for y (complex solution)
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8x+10y-8=-y^{2}
Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.
8x-8=-y^{2}-10y
Subtract 10y from both sides.
8x=-y^{2}-10y+8
Add 8 to both sides.
8x=8-10y-y^{2}
The equation is in standard form.
\frac{8x}{8}=\frac{8-10y-y^{2}}{8}
Divide both sides by 8.
x=\frac{8-10y-y^{2}}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{y^{2}}{8}-\frac{5y}{4}+1
Divide -y^{2}-10y+8 by 8.