Solve for A
\left\{\begin{matrix}A=C-\frac{B}{D}\text{, }&D\neq 0\\A\in \mathrm{R}\text{, }&B=0\text{ and }D=0\end{matrix}\right.
Solve for B
B=D\left(C-A\right)
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AD+B=CD
Swap sides so that all variable terms are on the left hand side.
AD=CD-B
Subtract B from both sides.
DA=CD-B
The equation is in standard form.
\frac{DA}{D}=\frac{CD-B}{D}
Divide both sides by D.
A=\frac{CD-B}{D}
Dividing by D undoes the multiplication by D.
A=C-\frac{B}{D}
Divide CD-B by D.
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