Solve +(1/10+10)^-1+10+10+(1/10+10)^-1+(1/2+2)^-1+(1/2+2)^-1+2=

$$+ ( \frac { 1 } { 10 + 10 } ) ^ { - 1 } + 10 + 10 + ( \frac { 1 } { 10 + 10 } ) ^ { - 1 } + ( \frac { 1 } { 2 + 2 } ) ^ { - 1 } + ( \frac { 1 } { 2 + 2 } ) ^ { - 1 } + 2 =$$

Evaluate

$$70$$

Solution Steps

Add 10 and 10 to get 20.

$$\left(\frac{1}{20}\right)^{-1}+10+10+\left(\frac{1}{10+10}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Calculate \frac{1}{20} to the power of -1 and get 20.

$$20+10+10+\left(\frac{1}{10+10}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Add 20 and 10 to get 30.

$$30+10+\left(\frac{1}{10+10}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Add 30 and 10 to get 40.

$$40+\left(\frac{1}{10+10}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Add 10 and 10 to get 20.

$$40+\left(\frac{1}{20}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Calculate \frac{1}{20} to the power of -1 and get 20.

$$40+20+\left(\frac{1}{2+2}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Add 40 and 20 to get 60.

$$60+\left(\frac{1}{2+2}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Add 2 and 2 to get 4.

$$60+\left(\frac{1}{4}\right)^{-1}+\left(\frac{1}{2+2}\right)^{-1}+2$$

Calculate \frac{1}{4} to the power of -1 and get 4.

$$60+4+\left(\frac{1}{2+2}\right)^{-1}+2$$

Add 60 and 4 to get 64.

$$64+\left(\frac{1}{2+2}\right)^{-1}+2$$

Add 2 and 2 to get 4.

$$64+\left(\frac{1}{4}\right)^{-1}+2$$

Calculate \frac{1}{4} to the power of -1 and get 4.

$$64+4+2$$

Add 64 and 4 to get 68.

$$68+2$$

Add 68 and 2 to get 70.

$$70$$

Factor

$$2\times 5\times 7$$