Solve +9/4+6/5*3-5/3*5=

$$+ \frac { 9 } { 4 } + \frac { 6 } { 5 \times 3 } - \frac { 5 } { 3 \times 5 } =$$

Evaluate

$$\frac{139}{60}\approx 2.316666667$$

Solution Steps

Multiply 5 and 3 to get 15.

$$\frac{9}{4}+\frac{6}{15}-\frac{5}{3\times 5}$$

Reduce the fraction \frac{6}{15} to lowest terms by extracting and canceling out 3.

$$\frac{9}{4}+\frac{2}{5}-\frac{5}{3\times 5}$$

Least common multiple of 4 and 5 is 20. Convert \frac{9}{4} and \frac{2}{5} to fractions with denominator 20.

$$\frac{45}{20}+\frac{8}{20}-\frac{5}{3\times 5}$$

Since \frac{45}{20} and \frac{8}{20} have the same denominator, add them by adding their numerators.

$$\frac{45+8}{20}-\frac{5}{3\times 5}$$

Add 45 and 8 to get 53.

$$\frac{53}{20}-\frac{5}{3\times 5}$$

Multiply 3 and 5 to get 15.

$$\frac{53}{20}-\frac{5}{15}$$

Reduce the fraction \frac{5}{15} to lowest terms by extracting and canceling out 5.

$$\frac{53}{20}-\frac{1}{3}$$

Least common multiple of 20 and 3 is 60. Convert \frac{53}{20} and \frac{1}{3} to fractions with denominator 60.

$$\frac{159}{60}-\frac{20}{60}$$

Since \frac{159}{60} and \frac{20}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{159-20}{60}$$

Subtract 20 from 159 to get 139.

$$\frac{139}{60}$$

Factor

$$\frac{139}{2 ^ {2} \cdot 3 \cdot 5} = 2\frac{19}{60} = 2.316666666666667$$