m^frac{1{2^k}}=1 lösen | Microsoft-Matheproblemlöser

Nach k auflösen

k\in \mathrm{R}

m=1

Nach m auflösen

\left\{\begin{matrix}\\m=1\text{, }&\text{unconditionally}\\m=-1\text{, }&Numerator(\frac{1}{2^{k}})\text{bmod}2=0\text{ and }Denominator(\frac{1}{2^{k}})\text{bmod}2=1\end{matrix}\right,

Quiz

Algebra

m ^ { \frac { 1 } { 2 ^ { k } } } = 1

Ähnliche Aufgaben aus Websuche

How do you simplify \displaystyle-{\left(-\frac{{t}}{{{3}{v}}}\right)}^{{-{{4}}}} ?

https://socratic.org/questions/how-do-you-simplify-t-3v-4

\displaystyle-\frac{{{81}{v}^{{4}}}}{{t}^{{4}}} Explanation: Another method or way of solving this is as follows; Using BODMAS \displaystyle-{\left(-\frac{{t}}{{{3}{v}}}\right)}^{{-{{4}}}} ...

Considering 0<s for the series \sum_{i=1}^{\infty} \frac {1}{i^s}, show that a_{2^{n+1} -1} <\sum_{j=0}^{n} ({\frac {1} {2^{s-1}})}^j.

https://math.stackexchange.com/questions/2155372/considering-0s-for-the-series-sum-i-1-infty-frac-1is-show-that

\begin{align} {\large\sum_{\normalsize i=1}^{\normalsize 2^{n+1}}}\frac{1}{i^s} &= \left[\frac{1}{1^s}\right]+\left[\frac{1}{2^s}+\frac{1}{3^s}\right]+\left[\frac{1}{4^s}+\frac{1}{5^s}+\frac{1}{6^s}+\frac{1}{7^s}\right]+\cdots+\left[\frac{}{}\cdots\frac{}{}\right]\color{red}{+\frac{1}{\left(2^{n+1}\right)^s}} \\[3mm] &\lt \left[\frac{1}{1^s}\right]+\left[\frac{1}{2^s}+\frac{1}{2^s}\right]+\left[\frac{1}{4^s}+\frac{1}{4^s}+\frac{1}{4^s}+\frac{1}{4^s}\right]+\cdots+\left[\frac{}{}\cdots\frac{}{}\right]\color{red}{+\frac{1}{\left(2^{n+1}\right)^s}} \\[3mm] &= \left[\frac{1}{1^s}\right]+\quad\left[\frac{2}{2^s}\right]\quad+\qquad\qquad\left[\frac{4}{4^s}\right]\qquad\qquad+\cdots+\left[\frac{2^n}{\left(2^n\right)^s}\right]\color{red}{+\frac{1}{\left(2^{n+1}\right)^s}} \\[3mm] &= \frac{1}{\left(2^0\right)^{s-1}}+\frac{1}{\left(2^1\right)^{s-1}}+\frac{1}{\left(2^2\right)^{s-1}}+\cdots+\frac{1}{\left(2^n\right)^{s-1}}\color{red}{+\frac{1}{\left(2^{n+1}\right)^s}} \\[3mm] &={\large\sum_{\normalsize j=0}^{\normalsize n}}\left(\frac{1}{2^{s-1}}\right)^j\color{red}{+\frac{1}{\left(2^{n+1}\right)^s}} \end{align} ...

1/24s^2=150

https://www.tiger-algebra.com/drill/1/24s~2=150/

1/24s2=150 Two solutions were found : s = 60 s = -60 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

How can I find the order of growth of this recurrence: T(n) =\sqrt{n}T\bigl(\sqrt{n}\bigr) + n

https://math.stackexchange.com/questions/1056643/how-can-i-find-the-order-of-growth-of-this-recurrence-tn-sqrtnt-bigl-sq

Thanks to Peter's comment, I found the solution: T(n) = n^{\frac{2^k - 1}{2^k}}\cdot T(n^{\frac{1}{2^k}}) + kn. Using not 1, but 2 as the stopping point: n^{\frac{1}{2^k}} = 2, which means that k = \log \log n ...

Probability that this truncated variable is equal to the original

https://math.stackexchange.com/questions/1054813/probability-that-this-truncated-variable-is-equal-to-the-original

Let us assume that you look for P(U = X) with U = 1_{(-\infty, c]}(X) X, with c>0. Then \begin{align} P(U = X) &= P(1_{(-\infty, c]}(X) X = X)\\ &= P(X=0 \text{ or } 1_{(-\infty, c]}(X) = 1)\\ ...

Evenly Spaced Integer Topology is Metrizable

https://math.stackexchange.com/q/1232215

The simplest argument is that X is regular, Hausdorff, and second countable and therefore metrizable by the Uryson metrization theorem. It’s second countable, since the base used to define it is ...

In die Zwischenablage kopiert

Beispiele

Quadratische Gleichung

{ x } ^ { 2 } - 4 x - 5 = 0

Trigonometrie

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

Simultane Gleichung

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Differenzierung

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

Integration

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Grenzwerte

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

Themen

Themen

Ähnliche Aufgaben aus Websuche

Teilen

Beispiele