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( 1,53 \cdot 3
(
1
,
5
3
⋅
3
Auswerten
4.59
4
.
5
9
Lösungsschritte anzeigen
Lösungsschritte
( 1,53 \cdot 3
(
1
,
5
3
⋅
3
Multiplizieren Sie 1.53 und 3, um 4.59 zu erhalten.
Multiplizieren Sie
1
.
5
3
und
3
, um
4
.
5
9
zu erhalten.
4.59
4
.
5
9
Faktorisieren
\frac{17 \cdot 3 ^ {3}}{2 ^ {2} \cdot 5 ^ {2}} = 4\frac{59}{100} = 4.59
2
2
⋅
5
2
1
7
⋅
3
3
=
4
1
0
0
5
9
=
4
.
5
9
Quiz
5 ähnliche Probleme wie:
( 1,53 \cdot 3
(
1
,
5
3
⋅
3
Ähnliche Aufgaben aus Websuche
What mass of precipitate should be obtained by the reaction between masses of \displaystyle{115}\cdot{g} \displaystyle{A}{g}{N}{O}_{{3}}{\left({a}{q}\right)} and \displaystyle{85}\cdot{g} ...
What mass of precipitate should be obtained by the reaction between masses of
1
1
5
⋅
g
A
g
N
O
3
(
a
q
)
and
8
5
⋅
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...
https://socratic.org/questions/592d8a4db72cff02472b22d7
Approx. \displaystyle{100}\cdot{g} \displaystyle{A}{g}{C}{l} precipitate should deposit........ Explanation: First we need a stoichiometric equation........ \displaystyle{2}{A}{g}{N}{O}_{{3}}{\left({a}{q}\right)}+{B}{a}{C}{l}_{{2}}{\left({a}{q}\right)}\rightarrow{2}{A}{g}{C}{l}{\left({s}\right)}\downarrow+{B}{a}{\left({N}{O}_{{3}}\right)}_{{2}} ...
Approx.
1
0
0
⋅
g
A
g
C
l
precipitate should deposit........ Explanation: First we need a stoichiometric equation........
2
A
g
N
O
3
(
a
q
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+
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a
C
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a
q
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→
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2
...
An \displaystyle{18}\cdot{m}{L} volume of \displaystyle{0.200}\cdot{m}{o}{l}\cdot{L}^{{-{{1}}}} \displaystyle{N}{a}_{{2}}{S}{O}_{{4}} is mixed with a \displaystyle{15}\cdot{m}{L} ...
An
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O
4
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5
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https://socratic.org/questions/598502117c0149746998f49b
We use the relationship \displaystyle\text{concentration}=\frac{\text{number of moles}}{\text{volume of solution}} , and get...... Explanation: We assume that the volumes are additive, and we ...
We use the relationship
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=
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What is wrong with that counting of S_{3}\times S_{3} subgroups?
What is wrong with that counting of
S
3
×
S
3
subgroups?
https://math.stackexchange.com/questions/1093206/what-is-wrong-with-that-counting-of-s-3-times-s-3-subgroups
Not every pair of order 2 elements generates a 2-Sylow subgroup. For example ((1 \ 2), 1) and ((2 \ 3), 1) generate S_3 \times 1.
Not every pair of order
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(
(
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2
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,
1
)
and
(
(
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3
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generate
S
3
×
1
.
Solve the congruencex^3+4x+8\equiv{0}\pmod{15}
Solve the congruence
x
3
+
4
x
+
8
≡
0
(
m
o
d
1
5
)
https://math.stackexchange.com/questions/302677/solve-the-congruencex34x8-equiv0-pmod15
Modulo 3, there is a solution: x\equiv 2\pmod{3} does work. But modulo 5, there is no solution. So there is no solution modulo 15. For if x^3+4x+8\equiv 0\pmod{15}, then x^3+4x+8\equiv 0\pmod{5} ...
Modulo
3
, there is a solution:
x
≡
2
(
m
o
d
3
)
does work. But modulo
5
, there is no solution. So there is no solution modulo
1
5
. For if
x
3
+
4
x
+
8
≡
0
(
m
o
d
1
5
)
, then
x
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4
x
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8
≡
0
(
m
o
d
5
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...
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What is the probability of rolling at least one
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https://math.stackexchange.com/q/278450
In answering this type of question, it is often useful to answer the opposite question! "At least..." immediately suggests multiple routes, with multiple calculations, while "never" is more easily ...
In answering this type of question, it is often useful to answer the opposite question! "At least..." immediately suggests multiple routes, with multiple calculations, while "never" is more easily ...
Four numbers are chosen from 1 to 20. If 1\leq k \leq 17, in how many ways is the difference between the smallest and the largest number equal to k?
Four numbers are chosen from 1 to 20. If
1
≤
k
≤
1
7
, in how many ways is the difference between the smallest and the largest number equal to k?
https://math.stackexchange.com/q/2098433
I will assume that numbers may not be repeated and that order of selection of the numbers does not matter., i.e. we are counting how many subsets, A, of \{1,2,\dots,20\} have the property that max(A)-min(A)=k ...
I will assume that numbers may not be repeated and that order of selection of the numbers does not matter., i.e. we are counting how many subsets,
A
, of
{
1
,
2
,
…
,
2
0
}
have the property that
m
a
x
(
A
)
−
m
i
n
(
A
)
=
k
...
Weitere Elemente
Teilen
Kopieren
In die Zwischenablage kopiert
4.59
Multiplizieren Sie 1.53 und 3, um 4.59 zu erhalten.
Beispiele
Quadratische Gleichung
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometrie
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Lineare Gleichung
y = 3x + 4
y
=
3
x
+
4
Arithmetisch
699 * 533
6
9
9
∗
5
3
3
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Simultane Gleichung
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Differenzierung
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Grenzwerte
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
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