{l}{A^C=B}{a=C}{text{Solvefor}btext{where}}{b=a} lösen | Microsoft-Matheproblemlöser

Nach A, C, B, a, b auflösen

b = C

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Lösen

A = 0, C = 0, a = 0, B = 0

A = - 1, C = 0, a = 0, B = 1

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5 ähnliche Probleme wie:

A^{C} = B a = C Solve for b where b = a

Ähnliche Aufgaben aus Websuche

Relationship between eigenvalues of

A^{T} A

B = [0 A A^{T} 0]

https://math.stackexchange.com/questions/2014959/relationship-between-eigenvalues-of-ata-and-b-left-beginarraycc-0-a

A^{⊤} A

is positive semidefinite, its eigenvalues,

μ_{1}, \dots, μ_{n}

, are nonnegative. The characteristic polynomial of

B

det (s I_{2 n} - B) = det [s I_{n} - A - A^{⊤} s I_{n}] = det (s^{2} I_{n} - A^{⊤} A)

Sufficient condition for the block matrix

(B A A^{T} 0)

to be invertible

https://math.stackexchange.com/questions/1027138/sufficient-condition-for-the-block-matrix-big-beginsmallmatrix-b-at-a

ker A = R Z

B u + A^{T} v = 0, A u = 0

u \in ker A = R Z

u = Z w

w

Z^{T} B Z w + Z^{T} A^{T} v = Z^{T} B Z w + (A Z)^{T} v = Z^{T} B Z w = 0

w = 0

Cholesky factor when adding a row and column to already factorized matrix

https://math.stackexchange.com/q/955874

To make this work, you should explicitly assume that

a^{t} A^{- 1} a < 1

; otherwise, the bordered matrix

B : = [A a^{t} a 1]

would not be positive definite anymore (and ...

Solve the Non-Homogeneous System

y^{'} = C y + b (t)

https://math.stackexchange.com/q/2801318

V = [11 1 - 1]

C = V [- 1 0 0 - 3] V^{- 1}

e^{C t} = V [e^{- t} 0 0 e^{- 3 t}] V^{- 1}

Solving systems of ODE'S in the form

\dot{u} = A u + b

https://math.stackexchange.com/questions/2034180/solving-systems-of-odes-in-the-form-dot-overrightarrowu-a-overrightarrow

You can use the method of undetermined coefficients or educated guessing to find a particular solution. Since

0

is not an eigenvalue of

A

b

is constant, look for a particular solution ...

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Beispiele

Quadratische Gleichung

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

Lineare Gleichung

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

Simultane Gleichung

{8 x + 2 y = 46 7 x + 3 y = 47

Differenzierung

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}