Datrys f(x)=(x-5)^3(x+4)^2

$$f ( x ) = ( x - 5 ) ^ { 3 } ( x + 4 ) ^ { 2 }$$

Enrhifo

$$\left(x+4\right)^{2}\left(x-5\right)^{3}$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} i ehangu'r \left(x-5\right)^{3}.

$$\left(x^{3}-15x^{2}+75x-125\right)\left(x+4\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(x+4\right)^{2}.

$$\left(x^{3}-15x^{2}+75x-125\right)\left(x^{2}+8x+16\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi x^{3}-15x^{2}+75x-125 â x^{2}+8x+16 a chyfuno termau tebyg.

$$x^{5}-7x^{4}-29x^{3}+235x^{2}+200x-2000$$

Ehangu

$$x^{5}-7x^{4}-29x^{3}+235x^{2}+200x-2000$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} i ehangu'r \left(x-5\right)^{3}.

$$\left(x^{3}-15x^{2}+75x-125\right)\left(x+4\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(x+4\right)^{2}.

$$\left(x^{3}-15x^{2}+75x-125\right)\left(x^{2}+8x+16\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi x^{3}-15x^{2}+75x-125 â x^{2}+8x+16 a chyfuno termau tebyg.

$$x^{5}-7x^{4}-29x^{3}+235x^{2}+200x-2000$$