Datrys ar gyfer a_n
a_{n}=\left(n+1\right)^{2}
Datrys ar gyfer n
n=-\left(\sqrt{a_{n}}+1\right)
n=\sqrt{a_{n}}-1\text{, }a_{n}\geq 0
Rhannu
Copïo i clipfwrdd
a_{n}=n^{2}+2n+1
Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(n+1\right)^{2}.
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