Datrys R_{1}=1140*10^-6muOmega.quadR_{2}=1000*10^-6muOmega.quadc_{1}=01mu5

$$R _ { 1 } = 1140 \times 10 ^ { - 6 } \mu \Omega . \quad R _ { 2 } = 1000 \times 10 ^ { - 6 } \mu \Omega . \quad c _ { 1 } = 01 \mu 5$$

Datrys ar gyfer R_1

$$R_{1}=\frac{57\Omega \mu }{50000}$$

Camau Ateb

Cyfrifo 10 i bŵer -6 a chael \frac{1}{1000000}.

$$R_{1}=1140\times \frac{1}{1000000}\mu \Omega$$

Lluosi 1140 a \frac{1}{1000000} i gael \frac{57}{50000}.

$$R_{1}=\frac{57}{50000}\mu \Omega$$

Datrys ar gyfer Ω

$$\left\{\begin{matrix}\Omega =\frac{50000R_{1}}{57\mu }\text{, }&\mu \neq 0\\\Omega \in \mathrm{R}\text{, }&R_{1}=0\text{ and }\mu =0\end{matrix}\right.$$

Camau ar gyfer Datrys Hafaliad Llinol

Cyfrifo 10 i bŵer -6 a chael \frac{1}{1000000}.

$$R_{1}=1140\times \frac{1}{1000000}\mu \Omega$$

Lluosi 1140 a \frac{1}{1000000} i gael \frac{57}{50000}.

$$R_{1}=\frac{57}{50000}\mu \Omega$$

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$\frac{57}{50000}\mu \Omega =R_{1}$$

Mae'r hafaliad yn y ffurf safonol.

$$\frac{57\mu }{50000}\Omega =R_{1}$$

Rhannu’r ddwy ochr â \frac{57}{50000}\mu .

$$\frac{50000\times \frac{57\mu }{50000}\Omega }{57\mu }=\frac{50000R_{1}}{57\mu }$$

Mae rhannu â \frac{57}{50000}\mu yn dad-wneud lluosi â \frac{57}{50000}\mu .

$$\Omega =\frac{50000R_{1}}{57\mu }$$