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Problemau tebyg o chwiliad gwe

Rhannu

50\left(1-\frac{1}{11040808032}\right)+\frac{100}{102^{5}}
Cyfrifo 102 i bŵer 5 a chael 11040808032.
50\left(\frac{11040808032}{11040808032}-\frac{1}{11040808032}\right)+\frac{100}{102^{5}}
Troswch y rhif degol 1 i’r ffracsiwn \frac{11040808032}{11040808032}.
50\times \frac{11040808032-1}{11040808032}+\frac{100}{102^{5}}
Gan fod gan \frac{11040808032}{11040808032} a \frac{1}{11040808032} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.
50\times \frac{11040808031}{11040808032}+\frac{100}{102^{5}}
Tynnu 1 o 11040808032 i gael 11040808031.
\frac{50\times 11040808031}{11040808032}+\frac{100}{102^{5}}
Mynegwch 50\times \frac{11040808031}{11040808032} fel ffracsiwn unigol.
\frac{552040401550}{11040808032}+\frac{100}{102^{5}}
Lluosi 50 a 11040808031 i gael 552040401550.
\frac{276020200775}{5520404016}+\frac{100}{102^{5}}
Lleihau'r ffracsiwn \frac{552040401550}{11040808032} i'r graddau lleiaf posib drwy dynnu a chanslo allan 2.
\frac{276020200775}{5520404016}+\frac{100}{11040808032}
Cyfrifo 102 i bŵer 5 a chael 11040808032.
\frac{276020200775}{5520404016}+\frac{25}{2760202008}
Lleihau'r ffracsiwn \frac{100}{11040808032} i'r graddau lleiaf posib drwy dynnu a chanslo allan 4.
\frac{276020200775}{5520404016}+\frac{50}{5520404016}
Lluosrif lleiaf cyffredin 5520404016 a 2760202008 yw 5520404016. Troswch \frac{276020200775}{5520404016} a \frac{25}{2760202008} yn ffracsiynau gyda’r enwadur 5520404016.
\frac{276020200775+50}{5520404016}
Gan fod gan \frac{276020200775}{5520404016} a \frac{50}{5520404016} yr un dynodydd, adiwch nhw drwy adio eu rhifiaduron.
\frac{276020200825}{5520404016}
Adio 276020200775 a 50 i gael 276020200825.