Datrys 12-1.75= | Microsoft Math Solver

Neidio i'r prif gynnwys

12 - 1.75

= 10.25

Enrhifo

10.25

Tick mark Image

Ffactor

\frac{4 1}{2 ^{2}} = 10 \frac{1}{4} = 10.25

Tick mark Image

Cwis

12 - 1.75 =

Problemau tebyg o chwiliad gwe

(- 1.0, 1.0)

https://math.stackexchange.com/q/1400702

Look at the atan2 function of your favourite programming language. It will compute an expression such as

arctan (\frac{y}{x})

for the first quadrant etc. Also note that the point you drew up has ...

What is the distance between

(- 7, 12, - 10)

(2, - 3, - 16)

https://socratic.org/questions/what-is-the-distance-between-7-12-10-and-2-3-16

342 \approx 18.493 to 3 dec. places

using the 3 dimensional form of the distance formula

• (x) d = (x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2} + (z_{2} - z_{1})^{2}

What is the distance between

(11, - 13, - 5)

(9, - 14, 4)

https://socratic.org/questions/what-is-the-distance-between-11-13-5-and-9-14-4

86 \approx 9.27 to 2 dec. places

using the 3-d version of the distance formula

• (x) d = (x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2} + (z_{2} - z_{1})^{2}

Proving that limit of a solution approaches equilibrium

https://math.stackexchange.com/questions/3054893/proving-that-limit-of-a-solution-approaches-equilibrium

Let's check how vector field defined by this system of ODEs behaves on the boundary of the rectangle

0 ⩽ x ⩽ 3, 0 ⩽ y ⩽ 4

. Let's denote it by

R

How to find condition on the constant term of a cubic equation with no square term such that the cubic equation has atleast two integer roots?

https://math.stackexchange.com/questions/2013854/how-to-find-condition-on-the-constant-term-of-a-cubic-equation-with-no-square-te

The local extrema of

f (x) = x^{3} - 27 x + k

f^{'} (x) = 3 x^{2} - 27 = 0

x = \pm 3

. If two roots of the cubic are to be real, then the third one must be real as well. Also, one of the roots must ...

Rhannu

Copïo i clipfwrdd

10.25

Tynnu 1.75 o 12 i gael 10.25.

Enghreifftiau

Hafaliad cwadratig

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

Hafaliad llinol

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

Hafaliad ar y pryd

{8 x + 2 y = 46 7 x + 3 y = 47

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}