Datrys (25p-15q)^2-(15p-25q)^2

$$( 25 p - 15 q ) ^ { 2 } - ( 15 p - 25 q ) ^ { 2 }$$

Enrhifo

$$400\left(p^{2}-q^{2}\right)$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(25p-15q\right)^{2}.

$$625p^{2}-750pq+225q^{2}-\left(15p-25q\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(15p-25q\right)^{2}.

$$625p^{2}-750pq+225q^{2}-\left(225p^{2}-750pq+625q^{2}\right)$$

I ddod o hyd i wrthwyneb 225p^{2}-750pq+625q^{2}, dewch o hyd i wrthwyneb pob term.

$$625p^{2}-750pq+225q^{2}-225p^{2}+750pq-625q^{2}$$

Cyfuno 625p^{2} a -225p^{2} i gael 400p^{2}.

$$400p^{2}-750pq+225q^{2}+750pq-625q^{2}$$

Cyfuno -750pq a 750pq i gael 0.

$$400p^{2}+225q^{2}-625q^{2}$$

Cyfuno 225q^{2} a -625q^{2} i gael -400q^{2}.

$$400p^{2}-400q^{2}$$

Ehangu

$$400p^{2}-400q^{2}$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(25p-15q\right)^{2}.

$$625p^{2}-750pq+225q^{2}-\left(15p-25q\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(15p-25q\right)^{2}.

$$625p^{2}-750pq+225q^{2}-\left(225p^{2}-750pq+625q^{2}\right)$$

I ddod o hyd i wrthwyneb 225p^{2}-750pq+625q^{2}, dewch o hyd i wrthwyneb pob term.

$$625p^{2}-750pq+225q^{2}-225p^{2}+750pq-625q^{2}$$

Cyfuno 625p^{2} a -225p^{2} i gael 400p^{2}.

$$400p^{2}-750pq+225q^{2}+750pq-625q^{2}$$

Cyfuno -750pq a 750pq i gael 0.

$$400p^{2}+225q^{2}-625q^{2}$$

Cyfuno 225q^{2} a -625q^{2} i gael -400q^{2}.

$$400p^{2}-400q^{2}$$