Datrys (2.5p-1.5q)^2-(1.5p-2.5q)^2

$$( 2.5 p - 1.5 q ) ^ { 2 } - ( 1.5 p - 2.5 q ) ^ { 2 }$$

Enrhifo

$$4\left(p^{2}-q^{2}\right)$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(2.5p-1.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(1.5p-2.5q\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(1.5p-2.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(2.25p^{2}-7.5pq+6.25q^{2}\right)$$

I ddod o hyd i wrthwyneb 2.25p^{2}-7.5pq+6.25q^{2}, dewch o hyd i wrthwyneb pob term.

$$6.25p^{2}-7.5pq+2.25q^{2}-2.25p^{2}+7.5pq-6.25q^{2}$$

Cyfuno 6.25p^{2} a -2.25p^{2} i gael 4p^{2}.

$$4p^{2}-7.5pq+2.25q^{2}+7.5pq-6.25q^{2}$$

Cyfuno -7.5pq a 7.5pq i gael 0.

$$4p^{2}+2.25q^{2}-6.25q^{2}$$

Cyfuno 2.25q^{2} a -6.25q^{2} i gael -4q^{2}.

$$4p^{2}-4q^{2}$$

Ehangu

$$4p^{2}-4q^{2}$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(2.5p-1.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(1.5p-2.5q\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(1.5p-2.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(2.25p^{2}-7.5pq+6.25q^{2}\right)$$

I ddod o hyd i wrthwyneb 2.25p^{2}-7.5pq+6.25q^{2}, dewch o hyd i wrthwyneb pob term.

$$6.25p^{2}-7.5pq+2.25q^{2}-2.25p^{2}+7.5pq-6.25q^{2}$$

Cyfuno 6.25p^{2} a -2.25p^{2} i gael 4p^{2}.

$$4p^{2}-7.5pq+2.25q^{2}+7.5pq-6.25q^{2}$$

Cyfuno -7.5pq a 7.5pq i gael 0.

$$4p^{2}+2.25q^{2}-6.25q^{2}$$

Cyfuno 2.25q^{2} a -6.25q^{2} i gael -4q^{2}.

$$4p^{2}-4q^{2}$$