Datrys (2x-1)^2-9=1

$$( 2 x - 1 ) ^ { 2 } - 9 = 1$$

Datrys ar gyfer x

$$x = \frac{\sqrt{10} + 1}{2} \approx 2.08113883$$

$$x=\frac{1-\sqrt{10}}{2}\approx -1.08113883$$

Camau drwy Ganfod Isradd

Adio 9 at ddwy ochr yr hafaliad.

$$\left(2x-1\right)^{2}-9+9=1+9$$

Mae tynnu 9 o’i hun yn gadael 0.

$$\left(2x-1\right)^{2}=1+9$$

Adio 1 at 9.

$$\left(2x-1\right)^{2}=10$$

Cymryd isradd dwy ochr yr hafaliad.

$$2x-1=\sqrt{10} 2x-1=-\sqrt{10}$$

Adio 1 at ddwy ochr yr hafaliad.

$$2x-1-\left(-1\right)=\sqrt{10}-\left(-1\right) 2x-1-\left(-1\right)=-\sqrt{10}-\left(-1\right)$$

Mae tynnu -1 o’i hun yn gadael 0.

$$2x=\sqrt{10}-\left(-1\right) 2x=-\sqrt{10}-\left(-1\right)$$

Tynnu -1 o \sqrt{10}.

$$2x=\sqrt{10}+1$$

Tynnu -1 o -\sqrt{10}.

$$2x=1-\sqrt{10}$$

Rhannu’r ddwy ochr â 2.

$$\frac{2x}{2}=\frac{\sqrt{10}+1}{2} \frac{2x}{2}=\frac{1-\sqrt{10}}{2}$$

Mae rhannu â 2 yn dad-wneud lluosi â 2.

$$x=\frac{\sqrt{10}+1}{2} x=\frac{1-\sqrt{10}}{2}$$