Datrys {l}{21=5I_{1}+6I_{2}}{14=10I_{3}+6I_{2}}{I_{1}=I_{2}-I_{3}}

$$\left. \begin{array}{l}{ 21 = 5 I _ { 1 } + 6 I _ { 2 } }\\{ 14 = 10 I _ { 3 } + 6 I _ { 2 } }\\{ I _ { 1 } = I _ { 2 } - I _ { 3 } }\end{array} \right.$$

Datrys ar gyfer I_1, I_2, I_3

$$I_{1} = \frac{9}{5} = 1\frac{4}{5} = 1.8$$

$$I_{2}=2$$

$$I_{3}=\frac{1}{5}=0.2$$

Camau Byr wrth Ddefnyddio Amnewid

Newid trefn yr hafaliadau.

$$I_{1}=I_{2}-I_{3} 14=10I_{3}+6I_{2} 21=5I_{1}+6I_{2}$$

Amnewid I_{2}-I_{3} am I_{1} yn yr hafaliad 21=5I_{1}+6I_{2}.

$$21=5\left(I_{2}-I_{3}\right)+6I_{2}$$

Datrys yr ail hafaliad ar gyfer I_{2} a'r trydydd hafaliad ar gyfer I_{3}.

$$I_{2}=\frac{7}{3}-\frac{5}{3}I_{3} I_{3}=\frac{11}{5}I_{2}-\frac{21}{5}$$

Amnewid \frac{7}{3}-\frac{5}{3}I_{3} am I_{2} yn yr hafaliad I_{3}=\frac{11}{5}I_{2}-\frac{21}{5}.

$$I_{3}=\frac{11}{5}\left(\frac{7}{3}-\frac{5}{3}I_{3}\right)-\frac{21}{5}$$

Datrys I_{3}=\frac{11}{5}\left(\frac{7}{3}-\frac{5}{3}I_{3}\right)-\frac{21}{5} ar gyfer I_{3}.

$$I_{3}=\frac{1}{5}$$

Amnewid \frac{1}{5} am I_{3} yn yr hafaliad I_{2}=\frac{7}{3}-\frac{5}{3}I_{3}.

$$I_{2}=\frac{7}{3}-\frac{5}{3}\times \frac{1}{5}$$

Cyfrifo I_{2} o I_{2}=\frac{7}{3}-\frac{5}{3}\times \frac{1}{5}.

$$I_{2}=2$$

Amnewid 2 am I_{2} a \frac{1}{5} am I_{3} yn yr hafaliad I_{1}=I_{2}-I_{3}.

$$I_{1}=2-\frac{1}{5}$$

Cyfrifo I_{1} o I_{1}=2-\frac{1}{5}.

$$I_{1}=\frac{9}{5}$$

Mae’r system wedi’i datrys nawr.

$$I_{1}=\frac{9}{5} I_{2}=2 I_{3}=\frac{1}{5}$$