Datrys {l}{z=2}{a={(8/2)}+{(6/2)}*{(40/7)}}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { z = 2 }\\ { a = {(\frac{8}{2})} + {(\frac{6}{2})} \cdot {(\frac{40}{7})} }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Datrys ar gyfer z, a, b, c

$$c = \frac{148}{7} = 21\frac{1}{7} \approx 21.142857143$$

Camau Ateb

Ystyriwch yr ail hafaliad. Rhannu 8 â 2 i gael 4.

$$a=4+\frac{6}{2}\times \frac{40}{7}$$

Rhannu 6 â 2 i gael 3.

$$a=4+3\times \frac{40}{7}$$

Lluosi 3 a \frac{40}{7} i gael \frac{120}{7}.

$$a=4+\frac{120}{7}$$

Adio 4 a \frac{120}{7} i gael \frac{148}{7}.

$$a=\frac{148}{7}$$

Ystyriwch y trydydd hafaliad. Mewnosod y gwerthoedd sy’n hysbys i’r hafaliad.

$$b=\frac{148}{7}$$

Ystyriwch y pedwaredd hafaliad. Mewnosod y gwerthoedd sy’n hysbys i’r hafaliad.

$$c=\frac{148}{7}$$

Mae’r system wedi’i datrys nawr.

$$z=2 a=\frac{148}{7} b=\frac{148}{7} c=\frac{148}{7}$$