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Problemau tebyg o chwiliad gwe

Rhannu

\frac{3\left(\sqrt{5}-\sqrt{2}\right)}{\left(\sqrt{5}+\sqrt{2}\right)\left(\sqrt{5}-\sqrt{2}\right)}+\frac{1}{3+\sqrt{8}}
Mae'n rhesymoli enwadur \frac{3}{\sqrt{5}+\sqrt{2}} drwy luosi'r rhifiadur a'r enwadur â \sqrt{5}-\sqrt{2}.
\frac{3\left(\sqrt{5}-\sqrt{2}\right)}{\left(\sqrt{5}\right)^{2}-\left(\sqrt{2}\right)^{2}}+\frac{1}{3+\sqrt{8}}
Ystyriwch \left(\sqrt{5}+\sqrt{2}\right)\left(\sqrt{5}-\sqrt{2}\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{3\left(\sqrt{5}-\sqrt{2}\right)}{5-2}+\frac{1}{3+\sqrt{8}}
Sgwâr \sqrt{5}. Sgwâr \sqrt{2}.
\frac{3\left(\sqrt{5}-\sqrt{2}\right)}{3}+\frac{1}{3+\sqrt{8}}
Tynnu 2 o 5 i gael 3.
\sqrt{5}-\sqrt{2}+\frac{1}{3+\sqrt{8}}
Canslo 3 a 3.
\sqrt{5}-\sqrt{2}+\frac{1}{3+2\sqrt{2}}
Ffactora 8=2^{2}\times 2. Ailysgrifennu ail isradd y lluoswm \sqrt{2^{2}\times 2} fel lluoswm ail israddau \sqrt{2^{2}}\sqrt{2}. Cymryd isradd 2^{2}.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)}
Mae'n rhesymoli enwadur \frac{1}{3+2\sqrt{2}} drwy luosi'r rhifiadur a'r enwadur â 3-2\sqrt{2}.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{3^{2}-\left(2\sqrt{2}\right)^{2}}
Ystyriwch \left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{9-\left(2\sqrt{2}\right)^{2}}
Cyfrifo 3 i bŵer 2 a chael 9.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{9-2^{2}\left(\sqrt{2}\right)^{2}}
Ehangu \left(2\sqrt{2}\right)^{2}.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{9-4\left(\sqrt{2}\right)^{2}}
Cyfrifo 2 i bŵer 2 a chael 4.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{9-4\times 2}
Sgwâr \sqrt{2} yw 2.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{9-8}
Lluosi 4 a 2 i gael 8.
\sqrt{5}-\sqrt{2}+\frac{3-2\sqrt{2}}{1}
Tynnu 8 o 9 i gael 1.
\sqrt{5}-\sqrt{2}+3-2\sqrt{2}
Mae rhannu unrhyw beth ag un yn rhoi'r rhif hwnnw.
\sqrt{5}-3\sqrt{2}+3
Cyfuno -\sqrt{2} a -2\sqrt{2} i gael -3\sqrt{2}.