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\frac{\frac{\frac{1}{2}}{\left(\frac{2}{3}\right)^{-1}}}{\left(1-\frac{1}{3}\right)\times \frac{9}{4}+\frac{1}{2}}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Calcula \sqrt[5]{\frac{1}{32}} i obté \frac{1}{2}.
\frac{\frac{\frac{1}{2}}{\frac{3}{2}}}{\left(1-\frac{1}{3}\right)\times \frac{9}{4}+\frac{1}{2}}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Calculeu \frac{2}{3} elevat a -1 per obtenir \frac{3}{2}.
\frac{\frac{1}{2}\times \frac{2}{3}}{\left(1-\frac{1}{3}\right)\times \frac{9}{4}+\frac{1}{2}}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Dividiu \frac{1}{2} per \frac{3}{2} multiplicant \frac{1}{2} pel recíproc de \frac{3}{2}.
\frac{\frac{1}{3}}{\left(1-\frac{1}{3}\right)\times \frac{9}{4}+\frac{1}{2}}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Multipliqueu \frac{1}{2} per \frac{2}{3} per obtenir \frac{1}{3}.
\frac{\frac{1}{3}}{\frac{2}{3}\times \frac{9}{4}+\frac{1}{2}}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Resteu 1 de \frac{1}{3} per obtenir \frac{2}{3}.
\frac{\frac{1}{3}}{\frac{3}{2}+\frac{1}{2}}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Multipliqueu \frac{2}{3} per \frac{9}{4} per obtenir \frac{3}{2}.
\frac{\frac{1}{3}}{2}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Sumeu \frac{3}{2} més \frac{1}{2} per obtenir 2.
\frac{1}{3\times 2}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Expresseu \frac{\frac{1}{3}}{2} com a fracció senzilla.
\frac{1}{6}+\frac{\sqrt{1-\frac{16}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Multipliqueu 3 per 2 per obtenir 6.
\frac{1}{6}+\frac{\sqrt{\frac{9}{25}}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Resteu 1 de \frac{16}{25} per obtenir \frac{9}{25}.
\frac{1}{6}+\frac{\frac{3}{5}}{\frac{\frac{4}{5}}{\left(\frac{15}{2}\right)^{1}}}
Torneu a escriure l'arrel quadrada de la divisió \frac{9}{25} com a divisió d'arrels quadrades \frac{\sqrt{9}}{\sqrt{25}}. Pren l'arrel quadrada del numerador i del denominador.
\frac{1}{6}+\frac{\frac{3}{5}}{\frac{\frac{4}{5}}{\frac{15}{2}}}
Calculeu \frac{15}{2} elevat a 1 per obtenir \frac{15}{2}.
\frac{1}{6}+\frac{\frac{3}{5}}{\frac{4}{5}\times \frac{2}{15}}
Dividiu \frac{4}{5} per \frac{15}{2} multiplicant \frac{4}{5} pel recíproc de \frac{15}{2}.
\frac{1}{6}+\frac{\frac{3}{5}}{\frac{8}{75}}
Multipliqueu \frac{4}{5} per \frac{2}{15} per obtenir \frac{8}{75}.
\frac{1}{6}+\frac{3}{5}\times \frac{75}{8}
Dividiu \frac{3}{5} per \frac{8}{75} multiplicant \frac{3}{5} pel recíproc de \frac{8}{75}.
\frac{1}{6}+\frac{45}{8}
Multipliqueu \frac{3}{5} per \frac{75}{8} per obtenir \frac{45}{8}.
\frac{139}{24}
Sumeu \frac{1}{6} més \frac{45}{8} per obtenir \frac{139}{24}.