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\frac{22}{21}\times 14\left(\left(\frac{35}{2}\right)^{2}+\left(\frac{38^{2}}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)
Multipliqueu \frac{1}{3} per \frac{22}{7} per obtenir \frac{22}{21}.
\frac{44}{3}\left(\left(\frac{35}{2}\right)^{2}+\left(\frac{38^{2}}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)
Multipliqueu \frac{22}{21} per 14 per obtenir \frac{44}{3}.
\frac{44}{3}\left(\frac{1225}{4}+\left(\frac{38^{2}}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)
Calculeu \frac{35}{2} elevat a 2 per obtenir \frac{1225}{4}.
\frac{44}{3}\left(\frac{1225}{4}+\left(\frac{1444}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)
Calculeu 38 elevat a 2 per obtenir 1444.
\frac{44}{3}\left(\frac{1225}{4}+722^{2}+\frac{35}{2}\times \frac{30}{2}\right)
Dividiu 1444 entre 2 per obtenir 722.
\frac{44}{3}\left(\frac{1225}{4}+521284+\frac{35}{2}\times \frac{30}{2}\right)
Calculeu 722 elevat a 2 per obtenir 521284.
\frac{44}{3}\left(\frac{2086361}{4}+\frac{35}{2}\times \frac{30}{2}\right)
Sumeu \frac{1225}{4} més 521284 per obtenir \frac{2086361}{4}.
\frac{44}{3}\left(\frac{2086361}{4}+\frac{35}{2}\times 15\right)
Dividiu 30 entre 2 per obtenir 15.
\frac{44}{3}\left(\frac{2086361}{4}+\frac{525}{2}\right)
Multipliqueu \frac{35}{2} per 15 per obtenir \frac{525}{2}.
\frac{44}{3}\times \frac{2087411}{4}
Sumeu \frac{2086361}{4} més \frac{525}{2} per obtenir \frac{2087411}{4}.
\frac{22961521}{3}
Multipliqueu \frac{44}{3} per \frac{2087411}{4} per obtenir \frac{22961521}{3}.